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Originally Posted by Casey Can anyone please help me with this?!?!? |
yes. I can.
For the first problem, first notice that the events are not independent, since P(R) * P(C) is not equal to P(R and C). This means that you can't use multiplication rule, and that P(R)=/=P(R|C). It's also the answer to letter d.
For the answer to letter a, draw a tree diagram, with the probability of a recession as the first branch and the other branches being whether or not there is a competing product in each case. It will look like attached figure J.1
Notice that P(R and C) is .25, which is one terminating end of our tree diagram, J.1
To find P(C|R) we remember that P(R) * P(C|R) = P(R and C), which describes the idea of conditional probability. Simply solve for P (C | R). that is, .25/.4
for letter b, we simply reverse the positions of the letters on the tree diagram like shown in diagram J.2
To find P(R|C), remember that P(C) * P(R | C) = P (R and C) and the process is similar the that for letter a. Solve like this: .25/.5
(it seems as if a recession occuring will affect whether or not a competing firm puts out a product, but that the competing firm producing does not affect whether or not there will be a recession. Makes sense, eh?
letter c calls for a venn diagram, drawn as in figure J3. Simply figure out the probabilities for each outcome that the problem lists (one, the other, and both) and add them together: .15+.25+.25= .65
We haven't done problems two or three yet in my class, but I'll take a look and post back later if I have a conclusive answer.