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Originally Posted by jbm222 In this case,
lim x-->0 x / sin(3x) = "0/0" <--- meets condition for L'Hopt.
Applying L'Hop
= lim x-->0 1 / 3*cos(3x) = 1 / 3*cos(0) = 1/3*1 = 1/3 |
You are making a mistake here.
x/sin(3x)=
(d/d(x))(x) / (d/d(x))(sin(3x))=
1 / (3*cos(3x)) (note: you could jump to the answer at this point)
(1/3) * (1/cos(3x))
(1/3) * sec(3x)
(1/3) * 1
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Originally Posted by jbm222 As far as Maru's method.... that might be easier for you, but that's one more formula to remember |
I would be inclined to agree. I made it through a year and a half of calculus without learning the u/sin(u) identity (and have yet to use it since I learned it), but don't think I would have made it through two weeks without knowing L'Hopital's rule.