Factoring Trinomials
Example #1:
(x + 2) (x + 3)
= x^2 + 3x + 2x + 6
= x^2 + 5x + 6
Note --> For the previous answer, the coefficent
+5 is the sum of
+3 and +2 and the coefficient
+6 is the product of
+2 and +3.
Example #2:
Question: x^2 - 6x + 8
From this we can see that:
*The SUM (middle number

) is
-6 and that
*The PRODUCT (last number

) is
+8
So the intergers have to be two numbers that when added together, create the sum of "-6" and when multiplied together, create the product of "+8"
From this bit of information we can come to the conclusion that
the integers would be -2 and -4
So now we have to complete the question by "inserting" the correct integers into the brackets, while keeping the same variable (oh gosh, I hope "variable" is the correct word LOL...by "variable" I mean "x" in this particular question

). Here is the full solution:
Question: x^2 - 6x + 8
Answer: = (x - 2) (x - 4)
Example #3:
Question: y^2 - 2xz - 48z^2
Sum: -2
Product: -48
Integers: -8, +6
Answer: = (y - 8z) (y + 6z)
Example #4:
2x^2 + 6x - 20
= 2 (x^2 + 3x - 10)
[note ---> see how I pulled out the GCF (2) first]
= 2 (x - 2) (x + 5)
Factoring Checklist:
1. Look for GCF
2. Factor trinomials