The Calculus Game

Amber · 02-20-2002, 08:39 AM

Here's a little something I thought up:

I will begin the game by posting a calculus problem. The first person who gets the correct answer AND posts the steps to solving the problem gets to post the next problem.

Here's an extremely simple one for starters:

Find the first derivative of the following equation:

y= x³ + x² - 8

No steps to solving are required for this problem.

By the way, (X^3) is X to the third power. Sorry, I don't know how type exponents.
Edit by Luke: I do.

-- <sup> and </sup>

perhaps · 02-21-2002, 09:34 PM

ahhh honey! dont scare me with that stuff!!
i will answer that when i take the Calc cousre...acutally, i'll probably be doing homework and not posting as often!!

Registered · 02-22-2002, 01:30 AM

Quote:

Originally posted by Amber
Here's a little something I thought up:

I will begin the game by posting a calculus problem. The first person who gets the correct answer AND posts the steps to solving the problem gets to post the next problem.

Here's an extremely simple one for starters:

Find the first derivative of the following equation:

y = x³ + x² - 8

No steps to solving are required for this problem.

y' = 3x² + 2x

Now, for the next question:
Maybe this is too easy,

Give an example of an imaginary number.

perhaps · 02-22-2002, 01:36 AM

um 6i?

lol, math is weird and hard to understand!

Luke · 02-22-2002, 04:42 AM

6i would be correct. Post another problem.

Amber · 02-22-2002, 07:25 AM

Quote:

Originally posted by Amber

By the way, (X^3) is X to the third power. Sorry, I don't know how type exponents.
Edit by Luke: I do.

How? That would make this game so much easier:kgrin:

Pipercostal · 02-22-2002, 07:57 AM

Of course the base imaginary number would be sqrt(-1).
More problems!!

Bryan · 02-22-2002, 09:11 AM

the 1st derivative of

y= log² x

Pipercostal · 02-22-2002, 09:33 AM

You had to make it base ten, didn't you?

y = log² x = ln² x / ln² 10
y' = 1/ln² 10 * (ln x * 1/ x + 1/x * ln x) From product rule
Thus
y' = (2 * ln x) / (ln² 10 * x)

Luke · 02-22-2002, 10:30 AM

I couldn't even remember the derivative of log() (or ln() for that matter). Impressive.

Luke · 02-22-2002, 10:32 AM

Wait, yes I do. I remember now, the integral of 1/x is ln(x), therefore the derivative of ln(x) dx is 1/x.

I'm retarded.

Luke · 02-22-2002, 10:38 AM

Please put the file within this ZIP file in your C:\WINDOWS\FONTS directory before continuing...

Luke · 02-22-2002, 10:40 AM

OK, let's try this one...straight from the CBFH (Calculus Book from Hell):

I (x - 1)^-1(x + 2)^-1 dx

Pipercostal · 02-22-2002, 10:42 AM

I barely remembered what the derivatie of ln was. Then again I haven't used Calculus for like 2 years now, since I graduated University. Man, I'm forgetting everything, including basic stuff relating to my degree. :kduh:

Luke · 02-22-2002, 10:44 AM

Then I'm guessing you won't be solving my above integral...