[Palivizumab]

I'm doing a practice test, but I don't know how to do these two problems.

Any tips or help?

[Peatrical]

For the first one go rb - ra, since you want the displacement between the two points So subtract the xcomponent a from the xcomponent b, and do the same with ys.
t
For b you want Fr to be dimensionless, you know g is in m/s^2, v m/s, and h is probably in m. (using fundamentals)

Using basic unit analysis:
So with out exponents you have (m/s) (m/s^2)(m) = m^3/s^3 but g is to the p and h is to the q and you want no dimensions: so you have in reality (m/s) (m/s^2)^p(m)^q = null.
So m*m^p*m^q = 0
and s-1*s^-2p = 0 From this we know the exponents must add up to 0, so -1 -2p=0. p =-1/2
So back to the meter expression: m*m^1/2 *m^q =0
So 1-1/2+q =0. q = -1/2 as well.

(m/s) (m/s^2)^(-1/2)(m)^(-1/2)

[Palivizumab]

Okay so number 19 would be D.

And 33 is B.

Awesome. Thank you so much.

[Peatrical]

Anytime.